Here is a problem that stumped me yesterday. Props to anyone who is clever enough to figure it out!
"A solution was prepared by mixing salt and water. A man found that the solution was too strong and he diluted 1350g of it with 750g of water. The new solution was then too weak so he added 1.2g of salt into the new solution and obtained a solution containing .9% salt. Find the percentage of salt in the original substance."
:-P
Here is a fun problem that is not exactly math, but is fun to think about.
"Three men walked into a hotel and intended to rent a room and split the cost between them. They were told it would be $30, so they each paid $10. The clerk then realized that the room cost only $25, so he sent the bellboy up with five $1 to refund the men. The bellboy did not know how to evenly refund the $5, so he gave each man $1 and kept the remaining $2. So, in effect, each man paid $9: He originally paid $10 and was given $1 back. So, (3 x 9 + 2 [the 2 that the bellboy kept] ) = 29. Where did the 30th dollar go?"
I actually don't think there's a solution; it's just a thinker. I think the problem lies when you say they paid $9 instead of $10, but I'm not sure.
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4 comments:
when i worked out the problem i got .00001 grams of salt
as for the dollar thing... i think your right it is just a math teaser
Bravo! I don't know if that's right or not, the answer isn't in the answer book, but it sounds good.
~JCP
*snicker* a rare idea. :-) Possibly true. Yeah, it actually makes sense.
~JCP
About the hotel one, I've read that somewhere else, and there is a solution to and if I remember right the last dollar went into the bellboys pocket, but don't ask me how it ends up like that, I can't remember. I do know that when I read why it was that way it made sense. You might try looking that up.
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